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Acid mine/rock drainage
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Lime precipitation
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Topic: Lime precipitation (Read 3162 times)
soza
Contributor
Posts: 1
Lime precipitation
«
on:
March 15, 2017, 06:33:04 PM »
I am trying to understand lime treatment reaction for mine flows. I want to be able to calculate the lime amount in "mg/L" similar to hardness removal in water treatment. please verify the logic below and advise on how to improve the code. Further, how to convert the units in output file?
TITLE Tria1, Part A.--MH WQ data.
SOLUTION 1 MH WQ
units ppm
pH 4.6
temp 10.0
Ca 375.0
Mg 2605.0
Na 79.0
K 0.0
Cl 20.20
Alkalinity 33.06 as HCO3
S(6) 12497.0 CHARGE
N(-3) 1.81
N(5) 0.5
Co 1.71
Al 15.6
Cu 1.71
Fe 317
Mn 38.2
Ni 4.6
Zn 10.41
END
TITLE Tria1, Part B.--RS WQ data
SOLUTION 2 RS WQ
units ppm
pH 3.8
temp 12.3
Ca 62.6
Mg 61.3
Na 41.0
K 0.0
Cl 27.7
S(6) 664.8 CHARGE
N(-3) 0.0
N(5) 2.4
Co 0.0
Al 26
Cu 2.1
Fe 0.047
Mn 61.3
Ni 0.2
Zn 0.9
END
TITLE Tria1, Part C.--EFPB WQ data
SOLUTION 3 EFPB WQ
units ppm
pH 6.82
temp 11.98
Ca 375.64
Mg 155.7
Na 324.72
K 0.0
Cl 99.64
S(6) 1963.4 CHARGE
N(-3) 9.83
N(5) 0.12
Co 0.0
Al 0.0
Cu 2.99
Fe 0.04
Mn 16.54
Ni 0.2
Zn 0.03
END
TITLE Mixing Three flows_Tria1, Part D.--Mix 70 MH, 30 RS, 40 EFPB.
MIX 1
1 70
2 40
3 40
SAVE solution 4
END
use solution 4
EQUILIBRIUM_PHASES 1
Calcite 0 0 precipitate_only
Dolomite 0 0 precipitate_only
TITLE Equilibrate with lime
REACTION 1
Portlandite 1
1 moles in 25 steps
USER_GRAPH 1
-headings x Ca Mg Na pH
-axis_titles "portlandite added in moles" "mg/l" "pH"
-chart_title "Portlandite Titration"
-initial_solutions false
-connect_simulations true
# -plot_concentration_vs x
-start
10 GRAPH_x step_no/25 #from 1 mol in 25 steps above
20 GRAPH_y tot("Ca") * 40.08e3
30 GRAPH_y tot("Mg") * 24.30e3
40 GRAPH_y tot("Na") * 23.00e3
50 GRAPH_SY -la("H+")
END
Logged
Farshad
Contributor
Posts: 1
Softening
«
Reply #1 on:
September 05, 2024, 11:16:58 AM »
Hello Every body
I want use PHREEQC to Softening water.
Could you please let me know where is my fault in coding ?
I added NaOH to reach pH to 7.9 and after that Na2CO3 , But Ca2+ is reduced very slightly:
PHASES
Calcite
CaCO3 = Ca+2 + CO3-2
log_k -8.48
delta_h -9.42 kcal
Brucite
Mg(OH)2 = Mg+2 + 2OH-
log_k -11.15
delta_h -10.5 kcal
SOLUTION 1 Initial_Water
temp 25
pH 7
pe 4
redox pe
units mg/l
density 1
Alkalinity 200 as HCO3
Ca 700
Cl 20
Mg 50
Na 10
C(4) 200
-water 1 # kg
REACTION 1
NaOH 0.1
0.0 0.01 # Adjust the amount of NaOH to achieve pH 7.9
SAVE solution 1
USER_GRAPH 1
-headings "NaOH" "Ca" "pH"
-axis_titles "NaOH(moles)" "Concentration (mg/L)" "pH"
-initial_solutions false
-connect_simulations true
-plot_concentration_vs x
-start
10 GRAPH_X RXN
20 GRAPH_Y MOL("Ca+2")
30 GRAPH_SY -LA("pH")
-end
USE solution 1
REACTION 2
Na2CO3 0.1
0.1 moles in 100 steps
USER_GRAPH 2
-headings "Na2CO3 (moles)" "Ca (mg/L)" "pH"
-axis_titles "Na2CO3 (moles)" "Concentration (mg/L)" "pH"
-initial_solutions false
-connect_simulations true
-plot_concentration_vs x
-start
10 GRAPH_X RXN
20 GRAPH_Y MOL("Ca+2")
30 GRAPH_SY -LA("pH")
-end
EQUILIBRIUM_PHASES 1
Brucite 0 0
Calcite 0 0
USE solution 1
EQUILIBRIUM_PHASES 2
Calcite 10^-6 10^-6
Brucite 0 0
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PhreeqcUsers Discussion Forum
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Acid mine/rock drainage
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Lime precipitation