Processes > Dissolution and precipitation

Temperature dependence of solubility of gypsum and anhydrite

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Aksenova:
Hello
I've read Example 2 in the manual.
And I have a question.
It contains a code that shows the solubility of gypsum and anhydrite in distilled water.
A liter of water was taken and 1 mole of each substance was added.
1 mole of anhydrite has a mass of 136 g.
1 mole of gypsum has a mass of 172 g.
Could you tell me, based on the code results from the example (attached below), how many grams were dissolved and how many remained?
According to reference data, the solubility of these minerals is very low.
--- Code: ---SOLUTION 1 Pure water
        pH      7.0
        temp    25.0               
EQUILIBRIUM_PHASES 1
        Gypsum          0.0     1.0
        Anhydrite       0.0     1.0
REACTION_TEMPERATURE 1
        25.0 75.0 in 51 steps
SELECTED_OUTPUT
        -file   ex2.sel
        -temperature
        -si     anhydrite  gypsum
USER_GRAPH 1 Example 2
        -headings Temperature Gypsum Anhydrite
        -chart_title "Gypsum-Anhydrite Stability"
        -axis_scale x_axis 25 75 5 0
        -axis_scale y_axis auto 0.05 0.1
        -axis_titles "Temperature, in degrees celsius" "Saturation index"
        -initial_solutions false
  -start
  10 graph_x TC
  20 graph_y SI("Gypsum") SI("Anhydrite")
  -end
END
--- End code ---

dlparkhurst:
You will have to look at the output to see how many moles of a mineral dissolved. You can then calculate the number of grams.

Aksenova:
Thank you. Got it.

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