Conceptual Models > Database selection and modification
Portlandite solubility high temperatures Pitzer
(1/1)
Lola12:
Hello,
I'm looking for simulating the portlandite solubility in satured brine (NaCl, presence of Ca, SO4, Mg) from 25?C to 100?C. Comparing the different databases, none correspond to my issue.
Thermoddem.dat is not for high ionic strength (I=6in my case)
Phreescale.dat do not have sulfates
Pitzer.dat; portlandite solubility is not a fonction of the temperature. :
"Portlandite
Ca(OH)2 = Ca+2 + 2 OH-
log_k -5.190"
Could I do the following modifications in my code?
#solubility of portlandite at 100?C
Phases
Portlandite(mdf)
Ca(OH)2 = Ca+2 + 2 OH-
-analytics -1.05 -0.000344 -238.15 -3.39e-1 0 -1.6071e-5
If you know a database i can use, I am also interested
Thanks for your time
dlparkhurst:
Yes, I think it is reasonable to use the temperature dependence from another database for Portlandite. Here is a selection from some databases.
sit.dat
Portlandite
Ca(OH)2 = 1.000Ca+2 - 2.000H+ + 2.000H2O
log_k 22.810 #10BLA/BOU1
delta_h -130.078 #kJ/mol
# Enthalpy of formation: -984.582 #kJ/mol
-analytic 2.13461E-2 0E+0 6.79444E+3 0E+0 0E+0
thermoddem
Portlandite
Ca(OH)2 + 2.000H+ = 1.000Ca+2 + 2.000H2O
log_k 22.812
delta_h -130.108 #kJ/mol #Internal calculation
-analytic -2.8492926E+2 -4.4710612E-2 2.1380115E+4 1.0420455E+2 -7.5424917E+5
#References = LogK/DGf: 10abla/bou; DHf/DHr: Internal calculation; S?: 98cha; Cp: 99aki/zot; V?: 95rob/hem;
minteq.v4
Portlandite
Ca(OH)2 + 2H+ = Ca+2 + 2H2O
log_k 22.804
delta_h -128.62 kJ
minteq, wateq4f
Portlandite
Ca(OH)2 + 2H+ = Ca+2 + 2H2O
log_k 22.675
delta_h -30.69 kcal
llnl.dat, core10
Portlandite
Ca(OH)2 +2.0000 H+ = + 1.0000 Ca++ + 2.0000 H2O
log_k 22.5552
-delta_H -128.686 kJ/mol # Calculated enthalpy of reaction Portlandite
# Enthalpy of formation: -986.074 kJ/mol
-analytic -8.3848e+001 -1.8373e-002 9.3154e+003 3.2584e+001 1.4538e+002
# -Range: 0-300
Lola12:
Thanks a lot. I will try it.
Navigation
[0] Message Index
Go to full version