TITLE Problem#1: Modeling Competitive Adsorption. Arsenic Adsorption Problem SOULTION_SPECIESCrO4-2 + 6H+ + 3e- = Cr(OH)2+ + 2H2O log_k 100. #67.376Cu+2 + e- = Cu+ log_k -100. #2.69END PHASES Ferrihydrite Fe(OH)3 + 3H+ = Fe+3 + 3H2O log_k 3.191 delta_h -73.374 kJFix_H+ H+ = H+ log_k 0 END SOLUTION 1 #Backgound water temp 25 pH 7.04 pe 4 Ferrihydrite 0 redox pe units mg/kgw density 1 As 0.000967 B 0.0468 Ba 0.037 C(4) 142 Ca 31.7 Cd 5.41e-005 Cl 15.8 Co 0.000138 Cr 0.0007797 Cu 0.00284 F 0.194 Fe 0.0792 K 2.51 Li 7.59e-3 Mg 8.9 Mn 0.012 Mo 0.000753 Na 25 Ni 0.0007778 Pb 0.000207 S 18.6 Sb 7.47e-005 Se 0.000557 Sr 0.219 V 0.0012 Zn 0.00761 -water 1 # kgEQUILIBRIUM_PHASES 1 Ferrihydrite 0 0.01 SURFACE 1 -equilibrate with solution 1 Hfo_wOH Ferrihydrite equilibrium_phase 0.2 600 Hfo_sOH Ferrihydrite equilibrium_phase 0.0025SAVE Solution 1 SAVE Equilibrium_phases 1SAVE Surface 1 END USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -5 Ca(OH)2; USE Surface 1; USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -6 Ca(OH)2; USE Surface 1; USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -7 Ca(OH)2; USE Surface 1; USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -8 Ca(OH)2; USE Surface 1; USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -9 Ca(OH)2; USE Surface 1; USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -10 Ca(OH)2; USE Surface 1;USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -11 Ca(OH)2; USE Surface 1; SOLUTION 2 #leachate temp 25 pH 5 pe 4 Ferrihydrite 0 redox pe units mg/kgw density 1 As 0.0723 B 1.73 Ba 0.0631 C(4) 19.3 Ca 117 Cd 0.00209 Cl 16.1 Co 0.00161 Cr 0.00144 Cu 0.002654 F 0.178 Fe 0.457 K 15.1 Li 0.17 Mg 2.92 Mn 0.109 Mo 0.35 Na 18.1 Ni 0.0134 Pb 0.000934 S 333 Sb 0.00453 Se 0.00784 Sr 1.02 V 0.0305 Zn 0.018 -water 1 # kgMIX 1 1 0 2 1SELECTED_OUTPUT 1 -file P1.AsAdsorptionProblem.csv -reset false -reaction false -pH true -totals CoEND
TITLE Problem#1: Modeling Competitive Adsorption. Arsenic Adsorption ProblemSOULTION_SPECIESCrO4-2 + 6H+ + 3e- = Cr(OH)2+ + 2H2O log_k 100. #67.376Cu+2 + e- = Cu+ log_k -100. #2.69END PHASESFerrihydrite Fe(OH)3 + 3H+ = Fe+3 + 3H2O log_k 3.191 delta_h -73.374 kJFix_H+ H+ = H+ log_k 0END SOLUTION 1 #Backgound water temp 25 pH 7.04 pe 4 Ferrihydrite 0 redox pe units mg/kgw density 1 As 0.000967 B 0.0468 Ba 0.037 C(4) 142 Ca 31.7 Cd 5.41e-005 Cl 15.8 Co 0.000138 Cr 0.0007797 Cu 0.00284 F 0.194 Fe 0.0792 K 2.51 Li 7.59e-3 Mg 8.9 Mn 0.012 Mo 0.000753 Na 25 Ni 0.0007778 Pb 0.000207 S 18.6 Sb 7.47e-005 Se 0.000557 Sr 0.219 V 0.0012 Zn 0.00761 -water 1 # kgEQUILIBRIUM_PHASES 1 Ferrihydrite 0 0.01 SURFACE 1 -equilibrate with solution 1 Hfo_wOH Ferrihydrite equilibrium_phase 0.2 600 Hfo_sOH Ferrihydrite equilibrium_phase 0.0025SAVE Solution 1SAVE Equilibrium_phases 1SAVE Surface 1ENDUSER_GRAPH10 GRAPH_X -LA("H+")20 GRAPH_Y TOT("Co")USE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -5 Ca(OH)2; USE Surface 1; ENDUSE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -6 Ca(OH)2; USE Surface 1; ENDUSE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -7 Ca(OH)2; USE Surface 1; ENDUSE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -8 Ca(OH)2; USE Surface 1; ENDUSE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -9 Ca(OH)2; USE Surface 1; ENDUSE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -10 Ca(OH)2; USE Surface 1; ENDUSE Solution 1; Equilibrium_phases 1; Ferrihydrite 0 0.1; Fix_H+ -11 Ca(OH)2; USE Surface 1; ENDEND