Processes > Mixing
Mixed step questions
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Jay Chou:
hello everyone
I have a question about solution mixing
Please see my process as follows:
I want to mix three solutions into one solution 4 in proportion, and then use the mixed solution for subsequent evaporation simulation
I followed the procedure in the instruction book and found that the solution used for the later evaporation simulation was not the mixed solution 4
I want to know which step is wrong with me? Thank you
SOLUTION 1 SMZB
temp 5
pH 9.16
pe 4
redox pe
units mg/l
density 1
Alkalinity 276.94
B 1.61
Ca 42.30
Cl 12.41
K 4.54
Li 1.84
Mg 27.40
Na 26.30
S(6) 36.04
-water 1 # kg
SOLUTION 2 qs
temp 5
pH 7.07
pe 4
redox pe
units mg/l
density 1
Alkalinity 290.4
B 5.35
Ca 55.20
Cl 64.8
K 28
Li 1.69
Mg 20
Na 195
S(6) 214.9
-water 1 # kg
SOLUTION 3 SM
temp 5
pH 8.7
pe 4
redox pe
units mg/l
density 1
Alkalinity 1145.86
B 626.6
Ca 1.55
Cl 869.82
K 139.2
Li 44.79
Mg 0.04
Na 976
S(6) 67.3
-water 1 # kg
MIX 1
1 2.3
2 1
3 1
save SOLUTION 4
END
EQUILIBRIUM_PHASES 1
Anhydrite 0 0 precipitate_only
Bischofite 0 0 precipitate_only
Bloedite 0 0 precipitate_only
Borax 0 0 precipitate_only
CO2(g) -3.4 100
Calcite 0 0 precipitate_only
Dolomite 0 0 precipitate_only
Epsomite 0 0 precipitate_only
Gaylussite 0 0 precipitate_only
Glaserite 0 0 precipitate_only
Glauberite 0 0 precipitate_only
Gypsum 0 0 precipitate_only
Halite 0 0 precipitate_only
Huntite 0 0 precipitate_only
K2B4O7:4H2O 0 0 precipitate_only
KB5O8:4H2O 0 0 precipitate_only
Kainite 0 0 precipitate_only
Li2CO3 0 0 precipitate_only
Li2SO4:H2O 0 0 precipitate_only
LiKSO4 0 0 precipitate_only
Magnesite 0 0 precipitate_only
Mirabilite 0 0 precipitate_only
NaB5O8:5H2O 0 0 precipitate_only
NaBO2:4H2O 0 0 precipitate_only
Pirssonite 0 0 precipitate_only
Polyhalite 0 0 precipitate_only
Sylvite 0 0 precipitate_only
Syngenite 0 0 precipitate_only
Thenardite 0 0 precipitate_only
Trona 0 0 precipitate_only
LiCl 0 0 precipitate_only
REACTION 1
H2O(g) -1
55.3 moles in 1 steps
USE SOLUTION 4
END
dlparkhurst:
I don't think anything is wrong with your mixing or use of SOLUTION 4. A run with no reaction shows that there are 4.3 kg water in solution 4.
--- Code: ---SOLUTION 1 SMZB
temp 5
pH 9.16
pe 4
redox pe
units mg/l
density 1
Alkalinity 276.94
B 1.61
Ca 42.30
Cl 12.41
K 4.54
Li 1.84
Mg 27.40
Na 26.30
S(6) 36.04
-water 1 # kg
SOLUTION 2 qs
temp 5
pH 7.07
pe 4
redox pe
units mg/l
density 1
Alkalinity 290.4
B 5.35
Ca 55.20
Cl 64.8
K 28
Li 1.69
Mg 20
Na 195
S(6) 214.9
-water 1 # kg
SOLUTION 3 SM
temp 5
pH 8.7
pe 4
redox pe
units mg/l
density 1
Alkalinity 1145.86
B 626.6
Ca 1.55
Cl 869.82
K 139.2
Li 44.79
Mg 0.04
Na 976
S(6) 67.3
-water 1 # kg
MIX 1
1 2.3
2 1
3 1
save SOLUTION 4
END
REACTION 1
USE SOLUTION 4
END
--- End code ---
Jay Chou:
Thank you very much for your reply. I have understood that the amount of water after mixing is determined by the mixing proportion.
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