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Author Topic: Mixed step questions  (Read 1664 times)

Jay Chou

  • Frequent Contributor
  • Posts: 12
Mixed step questions
« on: 17/11/22 12:54 »
hello everyone
I have a question about solution mixing
Please see my process as follows:
I want to mix three solutions into one solution 4 in proportion, and then use the mixed solution for subsequent evaporation simulation
I followed the procedure in the instruction book and found that the solution used for the later evaporation simulation was not the mixed solution 4
I want to know which step is wrong with me? Thank you

SOLUTION 1 SMZB
    temp      5
    pH        9.16
    pe        4
    redox     pe
    units     mg/l
    density   1
    Alkalinity 276.94
    B         1.61
    Ca        42.30
    Cl        12.41
    K         4.54
    Li        1.84
    Mg        27.40
    Na       26.30
    S(6)     36.04
    -water    1 # kg
SOLUTION 2 qs
    temp      5
    pH        7.07
    pe        4
    redox     pe
    units     mg/l
    density   1
    Alkalinity 290.4
    B         5.35
    Ca        55.20
    Cl        64.8
    K         28
    Li        1.69
    Mg        20
    Na       195
    S(6)     214.9
    -water    1 # kg
SOLUTION 3 SM
    temp      5
    pH        8.7
    pe        4
    redox     pe
    units     mg/l
    density   1
    Alkalinity 1145.86
    B         626.6
    Ca        1.55
    Cl        869.82
    K         139.2
    Li        44.79
    Mg        0.04
    Na       976
    S(6)     67.3
    -water    1 # kg
MIX 1
    1    2.3
    2    1
    3    1
save SOLUTION 4
END
EQUILIBRIUM_PHASES 1
    Anhydrite 0 0 precipitate_only
    Bischofite 0 0 precipitate_only
    Bloedite  0 0 precipitate_only
    Borax     0 0 precipitate_only
    CO2(g)    -3.4 100
    Calcite   0 0 precipitate_only
    Dolomite  0 0 precipitate_only
    Epsomite  0 0 precipitate_only
    Gaylussite 0 0 precipitate_only
    Glaserite 0 0 precipitate_only
    Glauberite 0 0 precipitate_only
    Gypsum    0 0 precipitate_only
    Halite    0 0 precipitate_only
    Huntite   0 0 precipitate_only
    K2B4O7:4H2O 0 0 precipitate_only
    KB5O8:4H2O 0 0 precipitate_only
    Kainite   0 0 precipitate_only
    Li2CO3    0 0 precipitate_only
    Li2SO4:H2O 0 0 precipitate_only
    LiKSO4    0 0 precipitate_only
    Magnesite 0 0 precipitate_only
    Mirabilite 0 0 precipitate_only
    NaB5O8:5H2O 0 0 precipitate_only
    NaBO2:4H2O 0 0 precipitate_only
    Pirssonite 0 0 precipitate_only
    Polyhalite 0 0 precipitate_only
    Sylvite   0 0 precipitate_only
    Syngenite 0 0 precipitate_only
    Thenardite 0 0 precipitate_only
    Trona     0 0 precipitate_only
    LiCl      0 0 precipitate_only
REACTION 1
    H2O(g)     -1
    55.3 moles in 1 steps
USE SOLUTION 4
END
Logged

dlparkhurst

  • Global Moderator
  • *****
  • Posts: 4035
Re: Mixed step questions
« Reply #1 on: 17/11/22 19:47 »
I don't think anything is wrong with your mixing or use of SOLUTION 4. A run with no reaction shows that there are 4.3 kg water in solution 4.

Code: [Select]
SOLUTION 1 SMZB
    temp      5
    pH        9.16
    pe        4
    redox     pe
    units     mg/l
    density   1
    Alkalinity 276.94
    B         1.61
    Ca        42.30
    Cl        12.41
    K         4.54
    Li        1.84
    Mg        27.40
    Na       26.30
    S(6)     36.04
    -water    1 # kg
SOLUTION 2 qs
    temp      5
    pH        7.07
    pe        4
    redox     pe
    units     mg/l
    density   1
    Alkalinity 290.4
    B         5.35
    Ca        55.20
    Cl        64.8
    K         28
    Li        1.69
    Mg        20
    Na       195
    S(6)     214.9
    -water    1 # kg
SOLUTION 3 SM
    temp      5
    pH        8.7
    pe        4
    redox     pe
    units     mg/l
    density   1
    Alkalinity 1145.86
    B         626.6
    Ca        1.55
    Cl        869.82
    K         139.2
    Li        44.79
    Mg        0.04
    Na       976
    S(6)     67.3
    -water    1 # kg
MIX 1
    1    2.3
    2    1
    3    1
save SOLUTION 4
END

REACTION 1

USE SOLUTION 4
END
Logged

Jay Chou

  • Frequent Contributor
  • Posts: 12
Re: Mixed step questions
« Reply #2 on: 18/11/22 01:53 »
Thank you very much for your reply. I have understood that the amount of water after mixing is determined by the mixing proportion.
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