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Calculating meq/l from meq/kg CEC (fractured rock)
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Topic: Calculating meq/l from meq/kg CEC (fractured rock) (Read 1078 times)
Felix
Frequent Contributor
Posts: 11
Calculating meq/l from meq/kg CEC (fractured rock)
«
on:
October 15, 2022, 04:51:59 PM »
Hello David and Phreeqc community!
I am trying to calculate a CEC for a paper and think my problem may be of interest to other readers:
A sandstone has 2.5% matrix porosity and is a fractured aquifer. The literature gives 50 meq/kg rock (50 mmol(c)/kg).
Appelo & Parkhurst (2005 Groundwater and Pollution, p. 248) give a calculation method that I adapt, but which seems to provide unrealistic values:
Quartz has 2.65 g/cm3, so 1 kg of dry sediment contains 1000/2.65 = 377mL.
Total sediment volume is 377/ (1-0.025) = 387mL
pore water: 387*0.025 = 9.7mL.
CEC = 50 meq/kg = 50/9.7 meq/mL = 5155 meq/L pore water (note conversion from mL to L).
But 5 moles CEC for the pore fluid seems crazy big. Appelo & Postma have 100 meq/l in their example (at 20% porosity). If the porosity becomes even smaller, 25 moles arise, and so on... (Isn't it the opposite: The less porosity, the less rock-fluid-contact?)
How would someone judge this value? Is there a more elegant way to calculate the CEC for my paper from the fracture volume*?
*I have about 6 fractures per meter with an opening of 0.5mm/fracture. This also gives very low values for the porosity...
I would be very grateful for some comments!
Kind regards
Felix
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dlparkhurst
Top Contributor
Posts: 3585
Re: Calculating meq/l from meq/kg CEC (fractured rock)
«
Reply #1 on:
October 16, 2022, 12:15:01 AM »
I would do the calculation a bit differently:
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0.975 (L rock) * 2.65 (kg/L rock) * 50 meq/kg = 129 meq
If you divide by the volume of water (0.025), you get essentially your result, 5167 meq/L water. If you are doing a batch calculation with ~1 L of water, this calculation would indicate a very large CEC per liter of water, and the number gets larger as the porosity decreases. The calculation assumes that all of the sites in the volume are accessible even as the volume of water decreases.
I think you are right to consider how many sites are available considering a rather limited surface that is exposed to the water. So, how was the value of 50 meq/kg rock measured? If you can estimate the surface area and that applies to that estimate (meq/m^2), you could make the calculation based on the surface area of the fractures relative to a liter of water.
You probably have a sufficiently difficult problem with the surface area, but I'll just mention that a TRANSPORT calculation can consider additional diffusion/exchange from the mobile zone (fracture) into a secondary porosity (side pores).
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Felix
Frequent Contributor
Posts: 11
Re: Calculating meq/l from meq/kg CEC (fractured rock)
«
Reply #2 on:
April 07, 2023, 11:01:24 AM »
Greetings David! My paper has been accepted by now, and I would like to thank for your response. I have resolved the issue as follows:
In the literature, powder was generated, which does not correspond to a fracture space. Moreover, there were no BET measurements available. I had to resort to an alternative approach. I derived the surface area geometrically based on the fracture aperture and the dimensions of the fracture. This enabled me to determine the water-rock contact geometrically in order to adjust the meq/kg to meq/L.
Indeed, the next time I would approach the chapter differently. For instance, I would follow the example presented in Example 13, "1D Transport in a Dual Porosity Column with Cation Exchange". As you previously mentioned, this example defines a stagnant/mobile interchange using the geometry of Van Genuchten (1985).
A question regarding this
: For sandstone-shale interbeds, I would use "plane sheets" as the shape factor instead of spheres. However, there is insufficient explanation on these planes in Van Genuchten (1985). Is this meant as a geological layer with a certain thickness? Or does Van Genuchten refer to a flat prism, like a "grain in the soil", similar to the cylinders and cubes that are further described?
Maybe you know more about this geometries?
Kind regards
Felix
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dlparkhurst
Top Contributor
Posts: 3585
Re: Calculating meq/l from meq/kg CEC (fractured rock)
«
Reply #3 on:
April 07, 2023, 02:14:57 PM »
Actually, I don't know much about geometries and shape factors. Example 21 gives a very complex example of diffusion.
Tony Appelo is the one who knows about these things, and the best choice would be to try to contact him. There may be more information at his web site hydrochemistry.eu.
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Felix
Frequent Contributor
Posts: 11
Re: Calculating meq/l from meq/kg CEC (fractured rock)
«
Reply #4 on:
April 09, 2023, 03:07:52 PM »
Hello David!
Okay, I will do it!
Thanks and best regards!
Felix
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