TITLE #MINERALS RECOVERY WITH WATERSOLUTION_SPECIESK+ + H2O = KOH + H+ log_k -14.46PHASESKOH(s)KOH = K+ + OH-log_k 2.18SOLUTION 1pH 4.5WATER 9.27 #9.27 Kg of water in 10 kg of wheyENDUSE solution 1#AMOUNT OF ALKALINE BATTERY 100 gEQUILIBRIUM_PHASES 1Pyrolusite 0 4.74 #MnO2 "Mol"Manganite 0 10.56 #MnOOH "Mol"#KOH(s) 0 4.48 #KOH "Mol"REACTIONKOH 11e-7 1e-6 1e-5 1e-4 1e-3 1e-2 1e-1 1 4.48USER_GRAPH 1 #Example Mn speciation -headings "Mn(OH)3-" "MnOH+" "Mn+2" -axis_titles "pH" "Fraction of Mn(2)" -chart_title "Mn(2) speciation (dissolved)" -axis_scale x_axis auto -axis_scale y_axis auto -start10 graph_y MOL("Mn(OH)3-")/TOT("Mn"), MOL("MnOH+")/TOT("Mn"), MOL("Mn+2")/TOT("Mn")20 graph_x -LA("H+")end