SOLUTION 1 Brineunits mol/LpH 8Na 8.436e-5Cl 8.330e-5As 2.5e-8SURFACE 1# assumes 1/10 of iron is HFOSurfOH 0.07 600. 30.-ccm 0.020983919END
SOLUTION_MASTER_SPECIES H H+ -1 H 1.008 H(0) H2 0 H H(1) H+ -1 1 E e- 0 1 1.008 O H2O 0 O 16 O(0) O2 0 O O(-2) H2O 0 1 As AsO4-3 -1.0 74.9216 74.9216 Na Na+ 0 Na 22.9898 Cl Cl- 0 Cl 35.453SOLUTION_SPECIESH+ = H+ log_k 0 -gamma 9 0 -dw 9.31e-009e- = e- log_k 0H2O = H2O log_k 0H2O = OH- + H+ -analytical_expression 293.29227 0.1360833 -10576.913 -123.73158 0 -6.996455e-005 -gamma 3.5 0 -dw 5.27e-009Na+ = Na+ -gamma 4.0 0.075 -gamma 4.08 0.082 # halite solubility -dw 1.33e-9 122 1.52 3.70 -Vm 2.28 -4.38 -4.1 -0.586 0.09 4 0.3 52 -3.33e-3 0.566 # ref. 1Cl- = Cl- -gamma 3.5 0.015 -gamma 3.63 0.017 # cf. pitzer.dat -dw 2.03e-9 194 1.6 6.9 -Vm 4.465 4.801 4.325 -2.847 1.748 0 -0.331 20.16 0 1 # ref. 12H2O = O2 + 4H+ + 4e- log_k -86.08 delta_h 134.79 kcal -dw 2.35e-0092H+ + 2e- = H2 log_k -3.15 delta_h -1.759 kcal -dw 5.13e-009Na+ + OH- = NaOH -log_k -10 AsO4-3 = AsO4-3 log_k 0.0AsO4-3 + 3H+ = H3AsO4 log_k 20.7H+ + AsO4-3 = HAsO4-2 log_k 11.502H+ + AsO4-3 = H2AsO4- log_k 18.46SURFACE_MASTER_SPECIESSurf SurfOHSURFACE_SPECIESSurfOH = SurfOHlog_k 0.0SurfOH + H+ = SurfOH2+log_k 7.29SurfOH = SurfO- + H+log_k -8.93SurfOH + AsO4-3 + 2H+ - OH- = SurfH2AsO4log_k 29.31SurfOH + AsO4-3 + H+ - OH- = SurfHAsO4- log_k 23.51SurfOH + AsO4-3 = SurfOHAsO4-3log_k 10.58